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2.78x^2-25=0
a = 2.78; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·2.78·(-25)
Δ = 278
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{278}}{2*2.78}=\frac{0-\sqrt{278}}{5.56} =-\frac{\sqrt{}}{5.56} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{278}}{2*2.78}=\frac{0+\sqrt{278}}{5.56} =\frac{\sqrt{}}{5.56} $
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